3.1.8 \(\int (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n (A+C \sin ^2(e+f x)) \, dx\) [8]
Optimal. Leaf size=257 \[ \frac {2^{\frac {1}{2}+n} c (C (1+2 m) (m-n)+(1+m+n) (C (1-m+n)+A (2+m+n))) \cos (e+f x) \, _2F_1\left (\frac {1}{2} (1+2 m),\frac {1}{2} (1-2 n);\frac {1}{2} (3+2 m);\frac {1}{2} (1+\sin (e+f x))\right ) (1-\sin (e+f x))^{\frac {1}{2}-n} (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{-1+n}}{f (1+2 m) (1+m+n) (2+m+n)}-\frac {C (1+2 m) \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n}{f (1+m+n) (2+m+n)}+\frac {C \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{1+n}}{c f (2+m+n)} \]
[Out]
2^(1/2+n)*c*(C*(1+2*m)*(m-n)+(1+m+n)*(C*(1-m+n)+A*(2+n+m)))*cos(f*x+e)*hypergeom([1/2+m, 1/2-n],[3/2+m],1/2+1/
2*sin(f*x+e))*(1-sin(f*x+e))^(1/2-n)*(a+a*sin(f*x+e))^m*(c-c*sin(f*x+e))^(-1+n)/f/(1+2*m)/(1+m+n)/(2+n+m)-C*(1
+2*m)*cos(f*x+e)*(a+a*sin(f*x+e))^m*(c-c*sin(f*x+e))^n/f/(1+m+n)/(2+n+m)+C*cos(f*x+e)*(a+a*sin(f*x+e))^m*(c-c*
sin(f*x+e))^(1+n)/c/f/(2+n+m)
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Rubi [A]
time = 0.45, antiderivative size = 257, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 6, integrand size = 38, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {3119, 3052,
2824, 2768, 72, 71} \begin {gather*} \frac {c 2^{n+\frac {1}{2}} ((m+n+1) (A (m+n+2)+C (-m+n+1))+C (2 m+1) (m-n)) \cos (e+f x) (1-\sin (e+f x))^{\frac {1}{2}-n} (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^{n-1} \, _2F_1\left (\frac {1}{2} (2 m+1),\frac {1}{2} (1-2 n);\frac {1}{2} (2 m+3);\frac {1}{2} (\sin (e+f x)+1)\right )}{f (2 m+1) (m+n+1) (m+n+2)}-\frac {C (2 m+1) \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^n}{f (m+n+1) (m+n+2)}+\frac {C \cos (e+f x) (a \sin (e+f x)+a)^m (c-c \sin (e+f x))^{n+1}}{c f (m+n+2)} \end {gather*}
Antiderivative was successfully verified.
[In]
Int[(a + a*Sin[e + f*x])^m*(c - c*Sin[e + f*x])^n*(A + C*Sin[e + f*x]^2),x]
[Out]
(2^(1/2 + n)*c*(C*(1 + 2*m)*(m - n) + (1 + m + n)*(C*(1 - m + n) + A*(2 + m + n)))*Cos[e + f*x]*Hypergeometric
2F1[(1 + 2*m)/2, (1 - 2*n)/2, (3 + 2*m)/2, (1 + Sin[e + f*x])/2]*(1 - Sin[e + f*x])^(1/2 - n)*(a + a*Sin[e + f
*x])^m*(c - c*Sin[e + f*x])^(-1 + n))/(f*(1 + 2*m)*(1 + m + n)*(2 + m + n)) - (C*(1 + 2*m)*Cos[e + f*x]*(a + a
*Sin[e + f*x])^m*(c - c*Sin[e + f*x])^n)/(f*(1 + m + n)*(2 + m + n)) + (C*Cos[e + f*x]*(a + a*Sin[e + f*x])^m*
(c - c*Sin[e + f*x])^(1 + n))/(c*f*(2 + m + n))
Rule 71
Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)/(b*(m + 1)*(b/(b*c
- a*d))^n))*Hypergeometric2F1[-n, m + 1, m + 2, (-d)*((a + b*x)/(b*c - a*d))], x] /; FreeQ[{a, b, c, d, m, n}
, x] && NeQ[b*c - a*d, 0] && !IntegerQ[m] && !IntegerQ[n] && GtQ[b/(b*c - a*d), 0] && (RationalQ[m] || !(Ra
tionalQ[n] && GtQ[-d/(b*c - a*d), 0]))
Rule 72
Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Dist[(c + d*x)^FracPart[n]/((b/(b*c - a*d)
)^IntPart[n]*(b*((c + d*x)/(b*c - a*d)))^FracPart[n]), Int[(a + b*x)^m*Simp[b*(c/(b*c - a*d)) + b*d*(x/(b*c -
a*d)), x]^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] && !IntegerQ[m] && !IntegerQ[n] &&
(RationalQ[m] || !SimplerQ[n + 1, m + 1])
Rule 2768
Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.), x_Symbol] :> Dist[a^2*(
(g*Cos[e + f*x])^(p + 1)/(f*g*(a + b*Sin[e + f*x])^((p + 1)/2)*(a - b*Sin[e + f*x])^((p + 1)/2))), Subst[Int[(
a + b*x)^(m + (p - 1)/2)*(a - b*x)^((p - 1)/2), x], x, Sin[e + f*x]], x] /; FreeQ[{a, b, e, f, g, m, p}, x] &&
EqQ[a^2 - b^2, 0] && !IntegerQ[m]
Rule 2824
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Dist
[a^IntPart[m]*c^IntPart[m]*(a + b*Sin[e + f*x])^FracPart[m]*((c + d*Sin[e + f*x])^FracPart[m]/Cos[e + f*x]^(2*
FracPart[m])), Int[Cos[e + f*x]^(2*m)*(c + d*Sin[e + f*x])^(n - m), x], x] /; FreeQ[{a, b, c, d, e, f, m, n},
x] && EqQ[b*c + a*d, 0] && EqQ[a^2 - b^2, 0] && (FractionQ[m] || !FractionQ[n])
Rule 3052
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*sin[(e_.) + (f_.)*(x_)])*((c_) + (d_.)*sin[(e_
.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[(-B)*Cos[e + f*x]*(a + b*Sin[e + f*x])^m*((c + d*Sin[e + f*x])^n/(f*
(m + n + 1))), x] - Dist[(B*c*(m - n) - A*d*(m + n + 1))/(d*(m + n + 1)), Int[(a + b*Sin[e + f*x])^m*(c + d*Si
n[e + f*x])^n, x], x] /; FreeQ[{a, b, c, d, e, f, A, B, m, n}, x] && EqQ[b*c + a*d, 0] && EqQ[a^2 - b^2, 0] &&
!LtQ[m, -2^(-1)] && NeQ[m + n + 1, 0]
Rule 3119
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.)*((A_.) + (C_.)*
sin[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[(-C)*Cos[e + f*x]*(a + b*Sin[e + f*x])^m*((c + d*Sin[e + f*x])^(
n + 1)/(d*f*(m + n + 2))), x] + Dist[1/(b*d*(m + n + 2)), Int[(a + b*Sin[e + f*x])^m*(c + d*Sin[e + f*x])^n*Si
mp[A*b*d*(m + n + 2) + C*(a*c*m + b*d*(n + 1)) - b*c*C*(2*m + 1)*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d
, e, f, A, C, m, n}, x] && EqQ[b*c + a*d, 0] && EqQ[a^2 - b^2, 0] && !LtQ[m, -2^(-1)] && NeQ[m + n + 2, 0]
Rubi steps
\begin {align*} \int (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n \left (A+C \sin ^2(e+f x)\right ) \, dx &=\frac {C \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{1+n}}{c f (2+m+n)}-\frac {\int (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n (-a c (C (1-m+n)+A (2+m+n))-a c C (1+2 m) \sin (e+f x)) \, dx}{a c (2+m+n)}\\ &=-\frac {C (1+2 m) \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n}{f (1+m+n) (2+m+n)}+\frac {C \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{1+n}}{c f (2+m+n)}+\frac {(C (1+2 m) (m-n)+(1+m+n) (C (1-m+n)+A (2+m+n))) \int (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n \, dx}{(1+m+n) (2+m+n)}\\ &=-\frac {C (1+2 m) \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n}{f (1+m+n) (2+m+n)}+\frac {C \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{1+n}}{c f (2+m+n)}+\frac {\left ((C (1+2 m) (m-n)+(1+m+n) (C (1-m+n)+A (2+m+n))) \cos ^{-2 m}(e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^m\right ) \int \cos ^{2 m}(e+f x) (c-c \sin (e+f x))^{-m+n} \, dx}{(1+m+n) (2+m+n)}\\ &=-\frac {C (1+2 m) \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n}{f (1+m+n) (2+m+n)}+\frac {C \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{1+n}}{c f (2+m+n)}+\frac {\left (c^2 (C (1+2 m) (m-n)+(1+m+n) (C (1-m+n)+A (2+m+n))) \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{\frac {1}{2} (-1-2 m)+m} (c+c \sin (e+f x))^{\frac {1}{2} (-1-2 m)}\right ) \text {Subst}\left (\int (c-c x)^{-m+\frac {1}{2} (-1+2 m)+n} (c+c x)^{\frac {1}{2} (-1+2 m)} \, dx,x,\sin (e+f x)\right )}{f (1+m+n) (2+m+n)}\\ &=-\frac {C (1+2 m) \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n}{f (1+m+n) (2+m+n)}+\frac {C \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{1+n}}{c f (2+m+n)}+\frac {\left (2^{-\frac {1}{2}+n} c^2 (C (1+2 m) (m-n)+(1+m+n) (C (1-m+n)+A (2+m+n))) \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{-\frac {1}{2}+\frac {1}{2} (-1-2 m)+m+n} \left (\frac {c-c \sin (e+f x)}{c}\right )^{\frac {1}{2}-n} (c+c \sin (e+f x))^{\frac {1}{2} (-1-2 m)}\right ) \text {Subst}\left (\int \left (\frac {1}{2}-\frac {x}{2}\right )^{-m+\frac {1}{2} (-1+2 m)+n} (c+c x)^{\frac {1}{2} (-1+2 m)} \, dx,x,\sin (e+f x)\right )}{f (1+m+n) (2+m+n)}\\ &=\frac {2^{\frac {1}{2}+n} c (C (1+2 m) (m-n)+(1+m+n) (C (1-m+n)+A (2+m+n))) \cos (e+f x) \, _2F_1\left (\frac {1}{2} (1+2 m),\frac {1}{2} (1-2 n);\frac {1}{2} (3+2 m);\frac {1}{2} (1+\sin (e+f x))\right ) (1-\sin (e+f x))^{\frac {1}{2}-n} (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{-1+n}}{f (1+2 m) (1+m+n) (2+m+n)}-\frac {C (1+2 m) \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^n}{f (1+m+n) (2+m+n)}+\frac {C \cos (e+f x) (a+a \sin (e+f x))^m (c-c \sin (e+f x))^{1+n}}{c f (2+m+n)}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 6 vs. order 5 in
optimal.
time = 15.68, size = 4861, normalized size = 18.91 \begin {gather*} \text {Result too large to show} \end {gather*}
Warning: Unable to verify antiderivative.
[In]
Integrate[(a + a*Sin[e + f*x])^m*(c - c*Sin[e + f*x])^n*(A + C*Sin[e + f*x]^2),x]
[Out]
(4*(16*C*AppellF1[1/2 + n, -2*m, 2*(1 + m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]
^2] + 128*C*AppellF1[1/2 + n, -2*m, 2*(2 + m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)
/4]^2] - A*AppellF1[1/2 + n, -2*m, 1 + 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/
4]^2] - C*AppellF1[1/2 + n, -2*m, 1 + 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4
]^2] - 80*C*AppellF1[1/2 + n, -2*m, 3 + 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)
/4]^2] - 64*C*AppellF1[1/2 + n, -2*m, 5 + 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*
x)/4]^2])*(Sec[(-e + Pi/2 - f*x)/4]^2)^(2*(m + n))*(2*A*Cos[(-e + Pi/2 - f*x)/2]^(2*m)*Sin[(-e + Pi/2 - f*x)/2
]^(2*n) + C*Cos[(-e + Pi/2 - f*x)/2]^(2*m)*Sin[(-e + Pi/2 - f*x)/2]^(2*n) + C*Cos[(-e + Pi/2 - f*x)/2]^(2*m)*C
os[2*(-e + Pi/2 - f*x)]*Sin[(-e + Pi/2 - f*x)/2]^(2*n))*(a + a*Sin[e + f*x])^m*(c - c*Sin[e + f*x])^n*Tan[(-e
+ Pi/2 - f*x)/4])/(f*(1 + 2*n)*(1 - Tan[(-e + Pi/2 - f*x)/4]^2)^(2*m)*((-8*m*(16*C*AppellF1[1/2 + n, -2*m, 2*(
1 + m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] + 128*C*AppellF1[1/2 + n, -2*m,
2*(2 + m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] - A*AppellF1[1/2 + n, -2*m, 1
+ 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] - C*AppellF1[1/2 + n, -2*m, 1
+ 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] - 80*C*AppellF1[1/2 + n, -2*m,
3 + 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] - 64*C*AppellF1[1/2 + n, -2*m
, 5 + 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2])*Cos[(-e + Pi/2 - f*x)/2]^(
2*m)*(Sec[(-e + Pi/2 - f*x)/4]^2)^(1 + 2*(m + n))*Sin[(-e + Pi/2 - f*x)/2]^(2*n)*Tan[(-e + Pi/2 - f*x)/4]^2*(1
- Tan[(-e + Pi/2 - f*x)/4]^2)^(-1 - 2*m))/(1 + 2*n) - (2*(16*C*AppellF1[1/2 + n, -2*m, 2*(1 + m + n), 3/2 + n
, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] + 128*C*AppellF1[1/2 + n, -2*m, 2*(2 + m + n), 3/2
+ n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] - A*AppellF1[1/2 + n, -2*m, 1 + 2*(m + n), 3/2 +
n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] - C*AppellF1[1/2 + n, -2*m, 1 + 2*(m + n), 3/2 +
n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] - 80*C*AppellF1[1/2 + n, -2*m, 3 + 2*(m + n), 3/2
+ n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] - 64*C*AppellF1[1/2 + n, -2*m, 5 + 2*(m + n), 3/
2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2])*Cos[(-e + Pi/2 - f*x)/2]^(2*m)*(Sec[(-e + Pi/
2 - f*x)/4]^2)^(1 + 2*(m + n))*Sin[(-e + Pi/2 - f*x)/2]^(2*n))/((1 + 2*n)*(1 - Tan[(-e + Pi/2 - f*x)/4]^2)^(2*
m)) - (8*n*(16*C*AppellF1[1/2 + n, -2*m, 2*(1 + m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 -
f*x)/4]^2] + 128*C*AppellF1[1/2 + n, -2*m, 2*(2 + m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/
2 - f*x)/4]^2] - A*AppellF1[1/2 + n, -2*m, 1 + 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2
- f*x)/4]^2] - C*AppellF1[1/2 + n, -2*m, 1 + 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2
- f*x)/4]^2] - 80*C*AppellF1[1/2 + n, -2*m, 3 + 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/
2 - f*x)/4]^2] - 64*C*AppellF1[1/2 + n, -2*m, 5 + 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + P
i/2 - f*x)/4]^2])*Cos[(-e + Pi/2 - f*x)/2]^(1 + 2*m)*(Sec[(-e + Pi/2 - f*x)/4]^2)^(2*(m + n))*Sin[(-e + Pi/2 -
f*x)/2]^(-1 + 2*n)*Tan[(-e + Pi/2 - f*x)/4])/((1 + 2*n)*(1 - Tan[(-e + Pi/2 - f*x)/4]^2)^(2*m)) + (8*m*(16*C*
AppellF1[1/2 + n, -2*m, 2*(1 + m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] + 128
*C*AppellF1[1/2 + n, -2*m, 2*(2 + m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] -
A*AppellF1[1/2 + n, -2*m, 1 + 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] - C
*AppellF1[1/2 + n, -2*m, 1 + 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] - 80
*C*AppellF1[1/2 + n, -2*m, 3 + 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] -
64*C*AppellF1[1/2 + n, -2*m, 5 + 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2])
*Cos[(-e + Pi/2 - f*x)/2]^(-1 + 2*m)*(Sec[(-e + Pi/2 - f*x)/4]^2)^(2*(m + n))*Sin[(-e + Pi/2 - f*x)/2]^(1 + 2*
n)*Tan[(-e + Pi/2 - f*x)/4])/((1 + 2*n)*(1 - Tan[(-e + Pi/2 - f*x)/4]^2)^(2*m)) - (8*(m + n)*(16*C*AppellF1[1/
2 + n, -2*m, 2*(1 + m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] + 128*C*AppellF1
[1/2 + n, -2*m, 2*(2 + m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] - A*AppellF1[
1/2 + n, -2*m, 1 + 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] - C*AppellF1[1
/2 + n, -2*m, 1 + 2*(m + n), 3/2 + n, Tan[(-e + Pi/2 - f*x)/4]^2, -Tan[(-e + Pi/2 - f*x)/4]^2] - 80*C*AppellF1
[1/2 + n, -2*m, 3 + 2*(m + n), 3/2 + n, Tan[(-e...
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Maple [F]
time = 0.70, size = 0, normalized size = 0.00 \[\int \left (a +a \sin \left (f x +e \right )\right )^{m} \left (c -c \sin \left (f x +e \right )\right )^{n} \left (A +C \left (\sin ^{2}\left (f x +e \right )\right )\right )\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
[In]
int((a+a*sin(f*x+e))^m*(c-c*sin(f*x+e))^n*(A+C*sin(f*x+e)^2),x)
[Out]
int((a+a*sin(f*x+e))^m*(c-c*sin(f*x+e))^n*(A+C*sin(f*x+e)^2),x)
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate((a+a*sin(f*x+e))^m*(c-c*sin(f*x+e))^n*(A+C*sin(f*x+e)^2),x, algorithm="maxima")
[Out]
integrate((C*sin(f*x + e)^2 + A)*(a*sin(f*x + e) + a)^m*(-c*sin(f*x + e) + c)^n, x)
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate((a+a*sin(f*x+e))^m*(c-c*sin(f*x+e))^n*(A+C*sin(f*x+e)^2),x, algorithm="fricas")
[Out]
integral(-(C*cos(f*x + e)^2 - A - C)*(a*sin(f*x + e) + a)^m*(-c*sin(f*x + e) + c)^n, x)
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (a \left (\sin {\left (e + f x \right )} + 1\right )\right )^{m} \left (- c \left (\sin {\left (e + f x \right )} - 1\right )\right )^{n} \left (A + C \sin ^{2}{\left (e + f x \right )}\right )\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate((a+a*sin(f*x+e))**m*(c-c*sin(f*x+e))**n*(A+C*sin(f*x+e)**2),x)
[Out]
Integral((a*(sin(e + f*x) + 1))**m*(-c*(sin(e + f*x) - 1))**n*(A + C*sin(e + f*x)**2), x)
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate((a+a*sin(f*x+e))^m*(c-c*sin(f*x+e))^n*(A+C*sin(f*x+e)^2),x, algorithm="giac")
[Out]
integrate((C*sin(f*x + e)^2 + A)*(a*sin(f*x + e) + a)^m*(-c*sin(f*x + e) + c)^n, x)
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \left (C\,{\sin \left (e+f\,x\right )}^2+A\right )\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^m\,{\left (c-c\,\sin \left (e+f\,x\right )\right )}^n \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
int((A + C*sin(e + f*x)^2)*(a + a*sin(e + f*x))^m*(c - c*sin(e + f*x))^n,x)
[Out]
int((A + C*sin(e + f*x)^2)*(a + a*sin(e + f*x))^m*(c - c*sin(e + f*x))^n, x)
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